§4.6.1 Ex=6.742 MeV

The 6.742 MeV state (Eres=330 keV) is thought to have Jπ=1/2- or 3/2- due to the l=1 character of its 20Ne(3He,α) angular distribution [Garret, Middleton et al. 1970]. A comparison of fits to the α-decay of this state using these assignments is shown in Figure 26. The Jπ=3/2- fit clearly does the better job, having a χ²/ν statistic of 1.96 versus 13.3 for the Jπ=3/2- fit.

Besids the total area, the only free parameter is p1/2, with a best fit value of 0.58 0.12 + 0.22 (see Figure 21a. Since this lies outside the allowable range of 0-0.5, and a new confidence region is found (see Figure 21b). The final result fit was Γ α / Γ = 0.888 0.030 + 0.091 with p1/2>0.44 at a 68.27% confidence level.

Placeholder for Figure 21.

Figure 21: The Ex=6.742 MeV confidence regions for the fit parameters. Circles mark the best-fit coordinates. The inner and outer contours are the boundaries for the 68.27% and 90% confidence levels, respectively. (a) The left panel shows the initial fit, which resulted in a non-physical value for p1/2. The physically allowed values are below and to the left of the lines. (b) The right panel shows the confidence regions obtained by not allowing p1/2>0.5.

UNDER CONSTRUCTION